(2a^2+4a+5)(5a-4)=

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Solution for (2a^2+4a+5)(5a-4)= equation: 


Simplifying
(2a2 + 4a + 5)(5a + -4) = 0

Reorder the terms:
(5 + 4a + 2a2)(5a + -4) = 0

Reorder the terms:
(5 + 4a + 2a2)(-4 + 5a) = 0

Multiply (5 + 4a + 2a2) * (-4 + 5a)
(5(-4 + 5a) + 4a * (-4 + 5a) + 2a2 * (-4 + 5a)) = 0
((-4 * 5 + 5a * 5) + 4a * (-4 + 5a) + 2a2 * (-4 + 5a)) = 0
((-20 + 25a) + 4a * (-4 + 5a) + 2a2 * (-4 + 5a)) = 0
(-20 + 25a + (-4 * 4a + 5a * 4a) + 2a2 * (-4 + 5a)) = 0
(-20 + 25a + (-16a + 20a2) + 2a2 * (-4 + 5a)) = 0
(-20 + 25a + -16a + 20a2 + (-4 * 2a2 + 5a * 2a2)) = 0
(-20 + 25a + -16a + 20a2 + (-8a2 + 10a3)) = 0

Combine like terms: 25a + -16a = 9a
(-20 + 9a + 20a2 + -8a2 + 10a3) = 0

Combine like terms: 20a2 + -8a2 = 12a2
(-20 + 9a + 12a2 + 10a3) = 0

Solving
-20 + 9a + 12a2 + 10a3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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